x=-0.02x^2+1.1x

Solution for x=-0.02x^2+1.1x equation:

x=-0.02x^2+1.1x

We move all terms to the left:

x-(-0.02x^2+1.1x)=0

We get rid of parentheses

0.02x^2-1.1x+x=0

We add all the numbers together, and all the variables

0.02x^2-0.1x=0

a = 0.02; b = -0.1; c = 0;
Δ = b2-4ac
Δ = -0.12-4·0.02·0
Δ = 0.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.1)-\sqrt{0.01}}{2*0.02}=\frac{0.1-\sqrt{0.01}}{0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.1)+\sqrt{0.01}}{2*0.02}=\frac{0.1+\sqrt{0.01}}{0.04}
$